给一个list查询哪些在表中哪些不在

select values from a list return that are in table and that are not in table

数据库 mysql

测试表

test table

name
wz
hl

---

查询的列表

select list

[ 'xm' ,'xw' ,'xl' ,'wz' ,'bt' ,'hh']

---

查询语句

select sql

select temp.name,if(temp.name = test.name,1,0) as 'is_null' from   (
select 'xm' as name
union all select 'xw'
union all select 'xl'
union all select 'wz'
union all select 'bt'
union all select 'hh'
) as temp
left join test on temp.name=test.name

return

name	is_null
xm	0
xw	0
xl	0
wz	1
bt	0
hh	0